Posted by Patrick on .
The force required to stretch a Hooke’slaw spring varies from 0 N to 70.4 N as we stretch the spring by moving one end 5.35 cm from its unstressed position.
Find the force constant of the spring. Answer in units of N/m

Physics 
Jennifer,
F = k*x
where F = force, x is displacement
70.4 = k*0.0535