Posted by amy on Friday, December 14, 2012 at 7:07pm.
what is 1500+lambda/2 ?
lambda=speedlight/frequency.
for ii0, draw the figure. use right triangle relationships, the hypotensue is 750+lambda/4, the base is 750, so figure h.
lambda works out to be 10^4m
so 1500+10^4/2=1505km
but i'm still stuck on how this is , why do you add the 1500?
ok i'm using pythagoras theorem but I'ts not working out right for me , thanks
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