The drawing shows a skateboarder moving at 6.41 m/s along a horizontal section of a track that is slanted upward by 47.4 ° above the horizontal at its end, which is 0.612 m above the ground. When she leaves the track, she follows the characteristic path of projectile motion. Ignoring friction and air resistance, find the maximum height H to whioch she rises above the end of the track.
Her final total energy is equal to the initial energy.
1/2 m vh^2 + mg(h+.612)=1/2 m 6.41^2
vh=6.41cos47.4
notice mass m divides out, solve for h.