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December 18, 2014

December 18, 2014

Posted by **Pat** on Friday, December 14, 2012 at 4:17pm.

A. log(A - B) = logA/logB

B. logA + logB = logAB

C. xloga = loga^x

D. log(b) b^x = x

- Math -
**Steve**, Friday, December 14, 2012 at 4:43pm(A)

it's log(A/B) = logA - logB

- Math -
**Steve**, Friday, December 14, 2012 at 4:43pmlogA/logB = log

_{A}B

- Math -
**Steve**, Friday, December 14, 2012 at 4:44pmoops. that's log

_{B}A

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