The pH of a liquid is a measure of how acidic or basic it is. The concentration of hydrogen ions in a liquid is labeled [H+]. Use the formula pH = –log[H+] to find the pH level, to the nearest tenth, of a liquid with [H+] about 5.4 x 10–14.

A. 14.7
B. 13.3
C. 14.0
D. -14.7

Just in case others are looking for the question just like this one:

The pH of a liquid is a measure of how acidic or basic it is. The concentration of hydrogen ions in a liquid is labeled [H+]. Use the formula pH = –log[H+] to find the pH level, to the nearest tenth, of a liquid with [H+] about 4.3x10^-14.

pH = -log(4.3 x 10^-14)
pH = -log(4.3) + 14
pH = 13.36 = 13.4

Answer: 13.4

pH = -log(5.4*10^-14)

= -log 5.4 + 14
= 14 - .732
= 13.268
Looks like (B)

The pH of a juice drink is 3.8. Find the concentration of hydrogen ions in the drink.

A) 3.8
B) 10^-3.8
C) 1.6×10^4
D) 1.6×10^-4

Your Angel from ABOVE, thank you so much 🥺

Well, well, well, looks like we have a pH problem here! Let's solve it with a splash of humor, shall we?

Using the formula pH = –log[H+], plug in the given concentration of hydrogen ions [H+] = 5.4 x 10–14. Now, let's calculate it without any clowning around!

pH = -log(5.4 x 10–14)

And the answer is... *drumroll* option C. 14.0!

So, the pH level of this liquid is 14.0, but don't worry, it's not too basic. It's just pH-tastic!

To find the pH level of a liquid with a given concentration of hydrogen ions [H+], you can use the formula pH = -log[H+]. In this case, the [H+] is approximately 5.4 x 10^-14.

1. Start by taking the logarithm (base 10) of the [H+].
log(5.4 x 10^-14)

2. Apply the logarithmic property to convert it into a negative exponent.
-log(5.4 x 10^-14)

3. Use the properties of logarithms to simplify the expression.
-(-14 + log(5.4))

4. Simplify further.
14 - log(5.4)

5. The logarithm of 5.4 can be calculated using a calculator, which is approximately 0.732.

6. Substitute the value of log(5.4) into the expression.
pH = 14 - 0.732

7. Calculate the value.
pH ≈ 13.268

To the nearest tenth, the pH level of the liquid is approximately 13.3.

Therefore, the correct answer is B. 13.3.