Posted by Anonymous on Friday, December 14, 2012 at 10:27am.
A horizontal slingshot consists of two light, identical springs (with spring constants of 37.7 N/m) and a light cup that holds a 1.37kg stone. Each spring has an equilibrium length of 50 cm. When the springs are in equilibrium, they line up vertically. Suppose that the cup containing the mass is pulled to x = 0.7 m to the left of the vertical and then released.

physics  bobpursley, Friday, December 14, 2012 at 11:14am
Is there a question here?

physics  Elena, Friday, December 14, 2012 at 12:47pm
(a) Stretch in the spring is
L₁=sqrt(x²+L₀²) = sqrt(0.7² +0.5²)=0.86 m
Elongation is
Δx= L₁L₀= 0.860.5=0.36 m.
E(total) = PE=2•k•Δx²/2=2•37.7•0.36²/2=4.9 J.
(b) PE=KE =mv²/2
v=sqrt(2•PE/m) = sqrt(2•4.9/1.37) = 2.67 m/s

physics  Anonymous, Sunday, July 20, 2014 at 2:09pm
A horizontal slingshot consists of two light, identical springs (with spring constants of 45.7 N/m) and a light cup that holds a 1.37kg stone. Each spring has an equilibrium length of 50 cm. When the springs are in equilibrium, they line up vertically. Suppose that the cup containing the mass is pulled to x = 0.7 m to the left of the vertical and then released. Determine
a) the system’s total mechanical energy.
Tries 0/4
b) the speed of the stone at x = 0.
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