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maths --plse help me..

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a train leaves kanyakumari for warengel on tuesday at 10:30 a.m if warengel 1586 km from kanyakuri when will it reach there if its speed is 39 km/h.

  • maths --plse help me.. -

    1586/39 = 40 2/3 hrs = 40 hrs 40 min

    arrive 10:30 + 40:40 = 50:70 = 2d+ 3:10
    so on Thur at 1:40 pm

  • maths --plse help me.. -

    I didn't understand after this,, plse help me to understand


    arrive 10:30 + 40:40 = 50:70 = 2d+ 3:10
    so on Thur at 1:40 pm

  • maths --plse help me.. -

    Distance is equal to rate times time
    Therefore time is equal to distance divided by rate.

    1586/39= 40 2/3 hours

    That means it takes 40 2/3 hours to go 1586 km when you are going 39 km per hour

    So if you start at 10:30 and go for 40 and 2/3 hours, which is 40 hours and 40 mins
    Start with the 40 mins that would take you to 11:10am
    Now 40 hours is 4 hours less than 48 hours which is 2 days... So you are 4 hours short of 11:10am on Thursday ....so I get 6:10am

  • maths --plse help me.. -

    Looks like we both blew it.
    I should have measured from midnight on Tue, making the time Thur at 3:10

    Mac should have subtracted 40 from 48 and gotten 8 hours less than 2 days, making the time Thur at 3:10

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