Homework Help: Chemistry

Posted by Odesa on Friday, December 14, 2012 at 1:20am.

You are conducting experiments with your x-ray diffractometer.

(a) A specimen of molybdenum is exposed to a beam of monochromatic x-rays of wavelength set by the Kα line of silver. Calculate the value of the smallest Bragg angle, θhkl, at which you can expect to observe reflections from the molybdenum specimen.

DATA:
λKα of Mo = 0.721 Å
lattice constant of Mo, a = 3.15 Å
λKα of Ag = 0.561 Å
lattice constant of Ag, a = 4.09 Å

(b) If you wish to repeat the experiment described in part (a) but using an electron diffractometer, across what vale of potential difference must electrons be accelerated from rest in order to give the identical value for the smallest Bragg angle, θhkl?

Chemistry - Anonymous, Friday, December 14, 2012 at 4:35am
Someone please answer this ;(
Chemistry - Anonymus, Friday, December 14, 2012 at 5:10am
3.93
Chemistry - Anonymus, Friday, December 14, 2012 at 5:21am
3.93 is correct?
Chemistry - Chemistry ;), Friday, December 14, 2012 at 5:55am
no ...
Chemistry - anonim, Friday, December 14, 2012 at 5:58am
a 7.23 is correct
Chemistry - anonymous, Friday, December 14, 2012 at 5:59am
and (b)?
Chemistry - anonymous, Friday, December 14, 2012 at 6:00am
How did you calculate it?
Chemistry - Ling, Friday, December 14, 2012 at 9:48am
What is b) ?
Chemistry - alex, Friday, December 14, 2012 at 11:04am
and b) is a voltage, needed to accelerate electrons to get the same sh*t.. :)
Chemistry - Steve, Friday, December 14, 2012 at 11:08am
What is the answer to B??
Chemistry - alex, Friday, December 14, 2012 at 11:17am
ok, b)

eV=E
To get electrons behave like a waves with the same lenght as 0.561A, we need to give them some impulse p according to de Broglie eq.
and E = p^2/2m..
Chemistry - babol, Friday, December 14, 2012 at 11:44am
to be honest i dont understand b)
it would be great to get a full detailed info
Chemistry - babalovic, Friday, December 14, 2012 at 11:51am
b) 475 ev
Chemistry - alex, Friday, December 14, 2012 at 11:58am
babol, for diffraction we need a wave, and according to de Broglie (and later experiments) any matter behave like a waves with different lengths ( depends on their energy). So actually we make a diffraction of electrons (as a waves) on a Mo surface.
Chemistry - Odesa, Friday, December 14, 2012 at 9:11pm
Thank you alex and babalovic for B)and anonim for A)

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