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October 1, 2014

October 1, 2014

Posted by **Anonymous** on Thursday, December 13, 2012 at 9:33pm.

Earth’s surface so that its weight is reduced

to 33.7 % of its weight at the Earth’s surface? The radius of the Earth is 6380 km

and the universal gravitational constant is

6.67 × 10

−11

N · m

2

/kg

2

.

Answer in units of km

- physics -
**Elena**, Friday, December 14, 2012 at 5:46ammg=GmM/R²

g=GM/R²

g´=GM/(R+h)²

g´= 0.337g

GM/(R+h)² =0.337• GM/R²

R²/0.337=(R+h)²= R²+2Rh+h²

h²+2Rh - 1.96R² = 0

h=- R±sqrt{R²+1.96 R²}=

=-R±1.72R

h=0.72R=0.72•6.38•10⁶=4.59•10⁶ m

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