Posted by **Anonymous** on Thursday, December 13, 2012 at 8:11pm.

A person walks the path shown below. The total trip consists of four straight-line paths.

Path 1 is 80.0 m due east.

Path 2 is 250.0 m due south.

Path 3 is 130.0 m 30.0° south of west.

Path 4 is 190.0 m 60.0° north of west.

At the end of the walk, what is the person's resultant displacement?

- physics -
**Jennifer**, Friday, December 14, 2012 at 4:08pm
Start the person at (0,0), and calculate the new position after each path.

After path 1: (80,0)

After path 2: (80, -250)

After path 3: x displacement is -130*cos30; y displacement is -130*sin30

(80 - 130*cos30, -250 -130*sin30)

After path 4: x displacement is -190*cos30, y displacement is 190*sin30;

New position is:

(80 - 130*cos30 - 190*cos30, -250 -130*sin30 + 190*sin30)

The magnitude of the displacement is (x^2 + y^2)^0.5, where (x,y) is the final position

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