Posted by Anonymous on Thursday, December 13, 2012 at 8:11pm.
A person walks the path shown below. The total trip consists of four straightline paths.
Path 1 is 80.0 m due east.
Path 2 is 250.0 m due south.
Path 3 is 130.0 m 30.0° south of west.
Path 4 is 190.0 m 60.0° north of west.
At the end of the walk, what is the person's resultant displacement?

physics  Jennifer, Friday, December 14, 2012 at 4:08pm
Start the person at (0,0), and calculate the new position after each path.
After path 1: (80,0)
After path 2: (80, 250)
After path 3: x displacement is 130*cos30; y displacement is 130*sin30
(80  130*cos30, 250 130*sin30)
After path 4: x displacement is 190*cos30, y displacement is 190*sin30;
New position is:
(80  130*cos30  190*cos30, 250 130*sin30 + 190*sin30)
The magnitude of the displacement is (x^2 + y^2)^0.5, where (x,y) is the final position
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