Homework Help: Physics

Posted by Bree on Thursday, December 13, 2012 at 8:09pm.

An arrow is shot straight upward at 55 m/s.
a) find the time until the arrow reaches its peak
b)how high was the arrow at its peak
c)find the total time the arrow is in the air
d)what was the velocity of the arrow after 3.5 seconds
e)how high was it at 3.5 seconds

Physics - Henry, Saturday, December 15, 2012 at 10:06pm
a. V = Vo + gt.
t = (V-Vo)g.
Tr = (0-55)/-9.8 = 5.6 s. = Rise time.

b. h = Vo*t + 0.5g*t^2.
h = 55*5.61 - 4.9*(5.61)^2 = 154.3 m.

c. Tf = Tr = 5.61 s.
Tr + Tf = 5.61 + 5.61 = 11.22 s. = Time
in air.

d. V=Vo + gt = 55 - 9.8*3.5 = 20.7 m/s.

e. h = Vo*t - 0.5g*t^2

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