posted by Bree on .
An arrow is shot straight upward at 55 m/s.
a) find the time until the arrow reaches its peak
b)how high was the arrow at its peak
c)find the total time the arrow is in the air
d)what was the velocity of the arrow after 3.5 seconds
e)how high was it at 3.5 seconds
a. V = Vo + gt.
t = (V-Vo)g.
Tr = (0-55)/-9.8 = 5.6 s. = Rise time.
b. h = Vo*t + 0.5g*t^2.
h = 55*5.61 - 4.9*(5.61)^2 = 154.3 m.
c. Tf = Tr = 5.61 s.
Tr + Tf = 5.61 + 5.61 = 11.22 s. = Time
d. V=Vo + gt = 55 - 9.8*3.5 = 20.7 m/s.
e. h = Vo*t - 0.5g*t^2