Homework Help: physics

Posted by Anonymous on Thursday, December 13, 2012 at 8:09pm.

A river flows due east at 1.50 m/s. A boat crosses the river from the south shore to the north shore by maintaining a constant velocity of 9.2 m/s due north relative to the water.
(a) What is the velocity of the boat as viewed by an observer on the shore?
m/s at ° east of north
(b) If the river is 301 m wide, how far downstream is the boat when it reaches the north shore?
m

physics - Henry, Saturday, December 15, 2012 at 9:23pm
X = 1.50 m/s.
Y = 9.2 m/s.

a. tanA = Y/X = 9.2/1.5 = 6.13333.
A = 80.7o, CCW.
A = 90-80.7 = 9.26o East of North.

b. tanA = 301/d.
d = 301/tanA = 301/tan80.7 = 49.3 m.
physics - Henry, Friday, March 1, 2013 at 5:23pm
a, V^2 = X^2 + Y^2 = 86.89
V = 9.32 m/s.

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