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algebra

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there was a total of 840 guests at a wedding dinner. 60% of them were adults, and the rest were children. some boys left before the dessert was served. as a result, the percentage of adults increased to 70%. how many boys left before the dessert was served

  • algebra - ,

    original:
    840 total
    504 adults
    336 children

    final
    840 - b total
    504 adults
    336 - b children

    so
    504 adults = .7(840 -b)
    all set?

  • algebra - ,

    b=132

  • algebra - ,

    120 boys left before dessert was served

  • algebra - ,

    60% = 504
    30% = 336

    Solve by Proportion
    504/336-x = 7/3

    2352 - 7x = 1512
    -7x = -840
    x = 120

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