there was a total of 840 guests at a wedding dinner. 60% of them were adults, and the rest were children. some boys left before the dessert was served. as a result, the percentage of adults increased to 70%. how many boys left before the dessert was served
120 boys left before dessert was served
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120
120 boys left
original:
840 total
504 adults
336 children
final
840 - b total
504 adults
336 - b children
so
504 adults = .7(840 -b)
all set?
b=132
60% = 504
30% = 336
Solve by Proportion
504/336-x = 7/3
2352 - 7x = 1512
-7x = -840
x = 120