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December 20, 2014

December 20, 2014

Posted by **lindsay** on Thursday, December 13, 2012 at 3:47pm.

4-{x-3}=0

PS. The brackets are supposed to be the straight lines for the absolute symbols.

- math -
**Steve**, Thursday, December 13, 2012 at 3:51pmwho are all these people that can't find the "|" key? It's shift-\ on every keyboard I've seen.

4-|x-3| = 0

if (x-3) > 0, |x-3| = x-3 and we have

4-(x-3) = 0

4-x+3 = 0

7-x = 0

x = 7

if (x-3) < 0, |x-3| = -(x-3) = 3-x

4-(3-x) = 0

1+x = 0

x = -1

Note that sometimes there are unusable solutions, as in some case where you have

if (x+3) > 5

and you end up with a "solution" of x = -2

which does not satisfy the condition.

In this problems, the solutions obeyed the conditions.

- math -
**Joey**, Thursday, December 13, 2012 at 3:52pmIn order to void the absolute value bars, it needs to stand by itself.

So 4=|x-3|

Now get rid of the value bars and you get:

7 = x

Plug it in and see !

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