Posted by Sam on Thursday, December 13, 2012 at 3:06pm.
Dave buys 3 green peppers and 2 red peppers for $3.45. Ruth buys 4 green peppers and 3 red peppers for $ 5.00. Find the price of each variety of pepper.
Algebra help - Joey, Thursday, December 13, 2012 at 3:16pm
This is one of those problems where you have to set up the peppers as variables. Lets say green peppers are "x" and red peppers are "y".
You can then make up a systems of equations to solve for each variable.
3x + 2y = 3.45
4x + 3y = 5.00
Now in order to solve each other you can use two techniques: one is to eliminate one term and solve for the other, or do substitution method.
I'm going to do the first one:
Now you can either cancel the "x" or "y" term. I'll choose "x"
Now in order to cancel, they have to be equal, but also one of them has to be a negative value.
4(3x+2y) = 4(3.45)
-3(4x+3y) = -3(5.00)
If you add each up you'd get:
12x+8y = 13.8
-12x-9y = -15
Which would end up being:
-y = -1.2
So y = $1.2
Now you can plug "y" back into any equation.
I'll pick Dave's:
3x + 2(1.2) = 3.45
So 3x + 2.4 = 3.45
3x = 1.05
x = $0.35
Now since we said x is green and y is red:
Green Peppers are 35 cents, and Red Peppers are 1.2 dollars.
In order to check, you can sub the x and y into Ruth's equation.
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