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December 20, 2014

December 20, 2014

Posted by **Sam** on Thursday, December 13, 2012 at 3:06pm.

- Algebra help -
**Joey**, Thursday, December 13, 2012 at 3:16pmThis is one of those problems where you have to set up the peppers as variables. Lets say green peppers are "x" and red peppers are "y".

You can then make up a systems of equations to solve for each variable.

Dave:

3x + 2y = 3.45

and

Ruth:

4x + 3y = 5.00

Now in order to solve each other you can use two techniques: one is to eliminate one term and solve for the other, or do substitution method.

I'm going to do the first one:

Now you can either cancel the "x" or "y" term. I'll choose "x"

Now in order to cancel, they have to be equal, but also one of them has to be a negative value.

So:

4(3x+2y) = 4(3.45)

-3(4x+3y) = -3(5.00)

If you add each up you'd get:

12x+8y = 13.8

-12x-9y = -15

Which would end up being:

-y = -1.2

So y = $1.2

Now you can plug "y" back into any equation.

I'll pick Dave's:

3x + 2(1.2) = 3.45

So 3x + 2.4 = 3.45

3x = 1.05

x = $0.35

Now since we said x is green and y is red:

Green Peppers are 35 cents, and Red Peppers are 1.2 dollars.

In order to check, you can sub the x and y into Ruth's equation.

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