Posted by **Cynthia** on Thursday, December 13, 2012 at 2:19pm.

The numbers iã5 and -iã5 are solutions to which equation?

a. x^2+ã5=0

b. x^2+5=0

d. x^2-5=0

- Algebra 2 -
**Cynthia**, Thursday, December 13, 2012 at 2:22pm
thank you do you know how to do it though?

- Algebra 2 -
**Steve**, Thursday, December 13, 2012 at 2:32pm
of course. I got the answer

you say √5i and -√5i are the solutions, so

(x-√5i)(x+√5i) = 0

x^2 - (√5i)^2 = 0

x^2 - 5i^2 = 0

but i^2 = -1, so

x^2 + 5 = 0

- Algebra 2 -
**Cynthia**, Thursday, December 13, 2012 at 2:35pm
omg thank you soooo much (:

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