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Math help

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Find the width of a recctangle that has a length of 48 cm a diagonal of 50 cm.

  • Math help - ,

    use Pythagoras

    w^2 + 48^2 = 50^2
    solve for w

  • Math help - ,

    d = diagonal

    L = Length

    W = Width


    d ^ 2 = L ^ 2 + W ^ 2

    50 ^ 2 = 48 ^ 2 + W ^ 2

    2500 = 2304 + W ^ 2 Subtract 2304 to both sides

    2500 - 2304 = 2304 + W ^ 2 - 2304

    196 = W ^ 2

    W = sqrt ( 196 )

    W = + OR - 14

    Width can't be negative so

    W = 14 cm

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