Posted by **Dawn** on Thursday, December 13, 2012 at 10:53am.

a bike passes a lamp post at the crest of hill at 4.5 m/s. she accelerates down the hill at the rate of 0.04 m/s squared for 12 seconds. how far does she move down the hill during this time ?

- Physics -
**Elena**, Thursday, December 13, 2012 at 11:05am
s=v₀t+at²/2,

v₀= 4.5 m/s,

a= 0.04 m/s²,

t= 12s

- Physics -
**Anonymous**, Thursday, November 6, 2014 at 6:33pm
d=V(initial)*time+1/2at^2

d=(4.5)(12)=1/2(0.40)(12)

d=54+1/2(4.8)

d=54+2.4

d=56.4m

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