Posted by Natasha on .
The flywheel of an engine has a moment of inertia of 24 kg*m^2.
a) if the radius of the wheel is 0.6m, what force is required to accelerate the wheel from rest to an angular velocity of 300 rpm in 6 seconds?
b) how many turns does it make during this time?
(a) compute the angular acceleration required in rad.s^2. Call it alpha
Torque = (moment of inertia)* (alpha)
= force * radius
Solve for force
(b) avg. rpm * (1 min/60s)* 6s
= 15 revolutions