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October 25, 2014

Posted by **confused--please help** on Wednesday, December 12, 2012 at 8:37pm.

f(x)=x^3-8x+9 a. from -3 to -2

b. from -1 to 5

c. from 5 to 9

A. what is average rate of change of f(x)=x^3-8x+9 from -3 to -2?

B. what is the average rate of change of f(x)-x^3-8x+9 from -1 to 5?

C. what is the average rate of change of f(x)=x^3-8x+9 from 5 to 9?

Please show work

- calculus -
**drwls**, Wednesday, December 12, 2012 at 8:49pmHow about if someone shows you how to do one and you do the rest?

The average of f'(x) over an interval a to b is the area under the f'(x) curve, divided by (b - a).

That equals f(b) - f(a), because the area under f'(x) dx is the integral, f(x)

A. f(-2) - f(-3) = -8 +16 +9

-(-27) -24 -9 = ?

- calculus -
**confused--please help**, Wednesday, December 12, 2012 at 9:16pma. is the answer -6

- calculus -
**drwls**, Wednesday, December 12, 2012 at 10:51pmThat is not what I get adding the numbers I gave you, but maybe I made a mistake.

I get +11

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