A 6.1 kg bowling ball is lifted 2.4 m into a

storage rack.
The acceleration of gravity is 9.8 m/s
2
.
Calculate the increase in the ball’s potential
energy.
Answer in units of J

PE= (M)(G)(H)

PE= (6.1)(9.8)(2.4)
PE= 155.232 J

To calculate the increase in the bowling ball's potential energy, we can use the formula:

Potential Energy = mass × gravitational acceleration × height

Given values:
Mass (m) = 6.1 kg
Gravitational acceleration (g) = 9.8 m/s^2
Height (h) = 2.4 m

Substituting the values into the formula, we get:

Potential Energy = 6.1 kg × 9.8 m/s^2 × 2.4 m

Multiplying these values, we get:

Potential Energy = 142.56 kg·m^2/s^2

Since the unit for potential energy is Joules (J), we can rewrite the answer as:

Potential Energy = 142.56 J

Therefore, the increase in the ball's potential energy is 142.56 J.

To solve this problem, we can use the formula for potential energy:

Potential Energy = mass * acceleration due to gravity * height

Given:
Mass of the bowling ball (m) = 6.1 kg
Acceleration due to gravity (g) = 9.8 m/s²
Height (h) = 2.4 m

Plugging in these values into the formula, we have:

Potential Energy = 6.1 kg * 9.8 m/s² * 2.4 m

Calculating this multiplication, we can find the increase in the ball's potential energy.

Potential Energy = 142.464 J

Therefore, the increase in the ball's potential energy is 142.464 Joules.

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