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Posted by on Wednesday, December 12, 2012 at 7:41pm.

log5(x+3)+log5(x-2)=log5(14)

  • Algebra - , Wednesday, December 12, 2012 at 10:34pm

    Log5(x+3)(x-2)=log5(14)
    (X+3)(x-2)=14
    X^2+x-6=14
    X^2+x-20=0
    (X+5)(x-4)=0
    X=-5, x=4
    -5 is not a true solution because you can't take the log of a negative number
    X=4

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