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posted by David on Wednesday, December 12, 2012 at 2:25pm.

Solve by completing the square: x^2+3x-28=0

x^2+3x-28 = 0 x^2+3x = 28 x^2 + 2(3/2)x + (3/2)^2 = 28 + (3/2)^2 (x + 3/2)^2 = 121/4 = (11/2)^2 x + 3/2 = ± 11/2 x = -3/2 ± 11/2 x = -7,4

Thanks steve

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