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Posted by Anonymous on Wednesday, December 12, 2012 at 10:53am.

Use the partial ractions to find The integral (3x^2-x+2)/(x-1)(x^2+1) dx

the integrand is x/(x^2+1)+2/(x-1) so integral is 1/2 log (x^2+1) + 2 log(x-1) = log [√(x^2+1)/(x-1)^2]

oops log [√(x^2+1)*(x-1)^2]

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