Wednesday

September 17, 2014

September 17, 2014

Posted by **Anonymous** on Wednesday, December 12, 2012 at 10:53am.

The integral (3x^2-x+2)/(x-1)(x^2+1) dx

- Maths - Integration by parts -
**Steve**, Wednesday, December 12, 2012 at 10:58amthe integrand is x/(x^2+1)+2/(x-1)

so integral is

1/2 log (x^2+1) + 2 log(x-1)

= log [√(x^2+1)/(x-1)^2]

- Maths - Integration by parts -
**Steve**, Wednesday, December 12, 2012 at 12:56pmoops

log [√(x^2+1)*(x-1)^2]

**Answer this Question**

**Related Questions**

integration by parts - s- integral s ln (2x+1)dx ? = ln(2x+1)x - s x d( ln (2x+1...

Maths-Integration by Partial Fraction - Use integration by partial fractions to ...

calc - evaluate the integral: y lny dy i know it's integration by parts but i ...

Math/Calculus - How would I integrate the following by parts: Integral of: (x^2...

Maths- Integration by partial fractions - Integral (3x^2-x+2)/(x-1)(x^2+1) dx

Math - Indefinite Integration - Use integration by parts to solve: I = f (x^3)(e...

Maths - Integration by parts - Integral x^2 sin(x) dx

calculus - Assuming that: Definite Integral of e^(-x^2) dx over [0,infinity] = ...

Cal - USE INTEGRATION BY PARTS TO FIND EACH INTEGRAL ƪxe^2x dx

CALCULUS - USE INTEGRATION BY PARTS TO FIND EACH INTEGRAL ƪxe^2x dx