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Posted by **Anonymous** on Wednesday, December 12, 2012 at 10:53am.

The integral (3x^2-x+2)/(x-1)(x^2+1) dx

- Maths - Integration by parts -
**Steve**, Wednesday, December 12, 2012 at 10:58amthe integrand is x/(x^2+1)+2/(x-1)

so integral is

1/2 log (x^2+1) + 2 log(x-1)

= log [√(x^2+1)/(x-1)^2]

- Maths - Integration by parts -
**Steve**, Wednesday, December 12, 2012 at 12:56pmoops

log [√(x^2+1)*(x-1)^2]

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