Homework Help: physics

Posted by Anonymous on Wednesday, December 12, 2012 at 8:53am.

It takes 2.5 J of energy to stretch a helical spring by 15 cm. Determine the spring
constant.

physics - Elena, Wednesday, December 12, 2012 at 5:11pm
PE=kx²/2
k=2•PE/ x²=
=2•2.5/0.15²=222 N/m

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