math
posted by britbrat on .
ind two consecutive even integers such that the smaller added to five times the larger is 58

Let the smaller even integer be n.
The larger is then n+2.
The problem says
"smaller added to five times the larger is 58"
which translates to
n+5(n+2)=58
Solve for n (smaller even integer) 
a = first number
b = second number
b = a + 2
a + 5 ( a + 2 ) = 58
a + 5 a + 10 = 58
6 a + 10 = 58 Subtrac 10 to both sides
6 a + 10  10 = 58  10
6 a = 48 Divide both sides by 6
6 a / 6 = 48 / 6
a = 8
b = a + 2 = 8 + 2 = 10
Your numbers are 8 and 10
8 + 5 * 10 = 8 + 50 = 58