Posted by **britbrat** on Wednesday, December 12, 2012 at 8:19am.

ind two consecutive even integers such that the smaller added to five times the larger is 58

- math -
**MathMate**, Wednesday, December 12, 2012 at 9:59am
Let the smaller even integer be n.

The larger is then n+2.

The problem says

"smaller added to five times the larger is 58"

which translates to

n+5(n+2)=58

Solve for n (smaller even integer)

- math -
**Bosnian**, Wednesday, December 12, 2012 at 11:25am
a = first number

b = second number

b = a + 2

a + 5 ( a + 2 ) = 58

a + 5 a + 10 = 58

6 a + 10 = 58 Subtrac 10 to both sides

6 a + 10 - 10 = 58 - 10

6 a = 48 Divide both sides by 6

6 a / 6 = 48 / 6

a = 8

b = a + 2 = 8 + 2 = 10

Your numbers are 8 and 10

8 + 5 * 10 = 8 + 50 = 58

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