Calculate the magnitude of the force required to cause an anterior dislocation of the glenohumeral joint given that he force has a lever arm of 52 cm, the maximum magnitude of the resistance force is 1080 N and the resistance force has a lever arm of 4.3 cm.
To calculate the magnitude of the force required to cause an anterior dislocation of the glenohumeral joint, we can use the principle of moments or torque.
Torque is calculated by multiplying the force by the lever arm. In this case, we have two forces and two lever arms. The force that causes the dislocation is the force we are trying to find.
Let's denote the force that causes the dislocation as F1, the lever arm for F1 as L1, the resistance force as F2, and the lever arm for F2 as L2. We also know the maximum magnitude of the resistance force, which is 1080 N.
Now, let's set up the equation for torque:
Torque caused by F1 = Torque caused by F2
F1 * L1 = F2 * L2
We are given that L1 = 52 cm and L2 = 4.3 cm. We can substitute these values into the equation:
F1 * 52 cm = 1080 N * 4.3 cm
To solve for F1, we need to convert the lever arms from centimeters to meters. There are 100 centimeters in 1 meter, so:
L1 = 52 cm = 0.52 m
L2 = 4.3 cm = 0.043 m
Now we can substitute the values:
F1 * 0.52 m = 1080 N * 0.043 m
To solve for F1, we divide both sides of the equation by 0.52:
F1 = (1080 N * 0.043 m) / 0.52 m
Calculating this, we get:
F1 = 89.077 N
Therefore, the magnitude of the force required to cause an anterior dislocation of the glenohumeral joint is approximately 89.077 Newtons.