Find the positive number such that 1/2 of the number multiplied by 1/3 of the number, multiplied by 1/6 of the number

is equal to the number itself.

x/2 * x/3 * x/6 = x

x^3/36 = x
x^3 = 36x
x^2 = 36
x = 6

check:
3*2*1 = 6

To find the positive number, let's call it "x," we can set up an equation based on the given information.

We know that 1/2 of the number, multiplied by 1/3 of the number, multiplied by 1/6 of the number is equal to the number itself.

Mathematically, this can be expressed as:

(1/2) * (1/3) * (1/6) * x = x

To solve this equation, we can simplify the left side by multiplying the fractions:

(1/2) * (1/3) * (1/6) = 1/36

Now we can rewrite the equation as:

(1/36) * x = x

We can multiply both sides of the equation by 36 to eliminate the fraction:

36 * (1/36) * x = 36 * x

This simplifies to:

x = 36 * x

Next, we'll bring all the terms with x to one side of the equation:

x - 36 * x = 0

Applying the distributive property:

1 * x - 36 * x = 0

Simplifying further:

x - 36x = 0

Combining like terms:

-35x = 0

To solve for x, we divide both sides of the equation by -35:

x = 0 / -35

Therefore, the positive number that satisfies the given condition is x = 0.

Note: It is important to mention that in this case, the only value that satisfies the equation is 0.