posted by Michelle on .
If 355 g Al(NO3)3 reacts with an excess of K2CrO4, how many moles of KNO3 would be produced?
2Al(NO3)3 + 3K2CrO4 ==> 6KNO3 + ?
mols Al(NO3)3 = grams/molar mass = ?
Convert to mols KNO3 using the coefficients in the balanced equation.
?mols Al(NO3)2 x [6 mol KNO3/2 mol Al(NO3)3]= ? = mols KNO3.