Posted by **Karan** on Wednesday, December 12, 2012 at 1:37am.

A rod of length L = 1.2 m pivots freely about one end. The rod is held horizontally and released, with no intial velocity. Find the angular velocity of the rod as it passes through the vertical orientation. (Use conservation of energy. The rotational inertia of a rod like this is I = (1/3)mL2.) The units are rad/s.

- physics -
**Karan**, Wednesday, December 12, 2012 at 1:41am
The answer I get is 12.24 rad/s. Can anyone confirm this?

- physics -
**Elena**, Wednesday, December 12, 2012 at 6:02am
PE =KE =KE(trans)+ KE(rot) =

mgL=mv²/2 +Iω²/2=

=m ω²L²/2 + m ω²L²/3•2=

=2 m ω²L²/3,

ω=sqrt(3g/2L)=sqrt(3•9.8/2•1.2) =

=sqrt(12.24)=3.5 rad/s

## Answer this Question

## Related Questions

- Physics - A nonuniform 2.0-kg rod is 2.0 m long. The rod is mounted to rotate ...
- physics - A uniform thin rod of length 0.55 m and mass 5.5 kg can rotate in a ...
- AP Physics - A uniform thin rod of length 0.3m and mass 3.5kg can rotate in a ...
- physics - A thin uniform rod is rotating at an angular velocity of 6.7 rad/s ...
- physics - A thin uniform rod is rotating at an angular velocity of 7.70 rad/s ...
- physics - A thin, uniform rod is hinged at its midpoint. To begin with, one-half...
- Physics - A thin, uniform rod is hinged at its midpoint. To begin with, one half...
- Physics - In the figure, a thin uniform rod of mass m = 3.05 kg and length L = 1...
- Physics - If a rod is moving at a velocity equal to 1/2 the speed of light ...
- physics - A uniform rod is set up so that it can rotate about a perpendicular ...

More Related Questions