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March 30, 2015

March 30, 2015

Posted by **Anonymous** on Tuesday, December 11, 2012 at 11:02pm.

a. How fast are they going at the bottom?

b. How long does it take them to go the 30 meters

- physics -
**Elena**, Wednesday, December 12, 2012 at 7:15amμ=0.14, s=30

m=160 kg

x: m•a= m•g•sinα - F(fr),

y: 0= - m•g•cosα +N.

F(fr)=μ•N= μ• m•g•cosα

m•a= m•g•sinα - μ• m•g•cosα

a= g(sinα - μ•cosα)

v=sqrt(2as)

t=v/a

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