Homework Help: physics

Posted by Betsalel on Tuesday, December 11, 2012 at 8:07pm.

A plank with m=0.12 kg and 50cm long has one mass of m1=0.11kg sitting on one end and a m2=0.055kg at the other end. Where should the pivot point be to balance the plank?

physics - Betsalel, Tuesday, December 11, 2012 at 8:26pm
I figured the equation out
Xcg=(m1x1+m2x2+m3(L/2))/(m1+m2+m3)

m1 = 0.055kg
x1 = 0cm

m2 = 0.11kg
x2 = 50cm

for the plank you need to add
m3 = 0.12kg
and distance is L=50cm

it calculates to Xcg=29.825cm

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