Posted by **brianna** on Tuesday, December 11, 2012 at 7:26pm.

find all discontinuities (16x/2x3-8x3=0)

- calculus -
**Reiny**, Tuesday, December 11, 2012 at 8:36pm
You are probably not getting a reply because this is a confusing question.

you write it as an equation, equations have solutions, we don't speak of discontinuities for equations

Secondly, is the denominator 2x^3 - 8x^3

or only 2x^3 , the way you typed it.

Thirdly, if the denominator is 2x^3 - 8x^3, why was it not simplified to -6x^3

Is there a typo??

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