If f(x) = 8x, neg 2 squared + 4x, 0 squared + 2x squared, what is the value of F(1/2)
If I interpret this right, in each case, just substitute 1/2 for x.
f(1/2) = 8(1/2) = ?
(-2)^2 = 4 Continue on with that.
0^2 = 0
Is the 2x squared (2x)^2 or 2x^2
To find the value of f(1/2), we need to substitute x = 1/2 into the function f(x).
Given that f(x) = 8x^2 + 4x^0 + 2x^2, we can simplify the equation:
f(x) = 8x^2 + 4(1) + 2x^2
Now, let's substitute x = 1/2 into the simplified equation:
f(1/2) = 8(1/2)^2 + 4(1) + 2(1/2)^2
To find the value of (1/2)^2, we need to square 1/2:
(1/2)^2 = (1/2) * (1/2) = 1/4
Now, we substitute (1/2)^2 back into the equation:
f(1/2) = 8(1/4) + 4(1) + 2(1/4)
Simplifying further:
f(1/2) = 2 + 4 + 1/2
Combining like terms:
f(1/2) = 6 + 1/2
To add fractions with different denominators, we need to find a common denominator:
f(1/2) = 6/1 + 1/2
To add fractions, we need the same denominator:
f(1/2) = 12/2 + 1/2
Now that the fractions have the same denominator, we can add them:
f(1/2) = 13/2
Therefore, the value of f(1/2) is 13/2.