2NaClO2---> 2NaCl + 3O2
if 3.85 grams of NaClO3 react, how many moles of O2 are created?
You have a typo somewhere. NaClO2 in the equation; NaClO3 in the problem.
mols NaClOx = grams/molar mass
Convert mols NaClOx to mols O2 using the coefficients in the balanced equation.
To find the number of moles of O2 created in the reaction, we need to use the balanced chemical equation and the molar ratio between NaClO3 and O2.
Let's break down the information given in the balanced chemical equation:
2NaClO3 -> 2NaCl + 3O2
From the equation, we can see that for every 2 moles of NaClO3, 3 moles of O2 are produced.
Next, we need to calculate the number of moles of NaClO3:
Given that the mass of NaClO3 is 3.85 grams, we need to convert this mass to moles. To do this, we will use the molar mass of NaClO3.
The molar mass of NaClO3 can be determined by adding the atomic masses of the elements present in the compound:
Na (sodium) = 22.99 g/mol
Cl (chlorine) = 35.45 g/mol
O (oxygen) = 16.00 g/mol (there are three oxygen atoms in NaClO3)
Summing up the atomic masses:
Na = 1 x 22.99 = 22.99 g/mol
Cl = 1 x 35.45 = 35.45 g/mol
O = 3 x 16.00 = 48.00 g/mol
Molar mass of NaClO3 = 22.99 + 35.45 + 48.00 = 106.44 g/mol
Now, we can use the molar mass to convert grams to moles:
Moles of NaClO3 = Mass / Molar mass = 3.85 g / 106.44 g/mol
Calculating the moles of NaClO3:
Moles of NaClO3 = 0.0362 mol (rounded to four decimal places)
Finally, we can use the mole ratio to find the moles of O2 produced:
According to the balanced chemical equation, we know that for every 2 moles of NaClO3, 3 moles of O2 are produced.
So, the number of moles of O2 produced =
Moles of NaClO3 x (Moles of O2 / Moles of NaClO3) = 0.0362 mol x (3 mol O2 / 2 mol NaClO3)
Calculating the moles of O2:
Moles of O2 = 0.0362 mol x (3/2) = 0.0543 mol (rounded to four decimal places)
Therefore, 3.85 grams of NaClO3 will produce approximately 0.0543 moles of O2.