If the 12.5ml of NaOH solution is required to react completely with 0.300g of KHP (Potassium Hydrogen Phthalate, 204.2g/mol). What is the molarity of NaOH?

NaOH + KHP ==> NaKP + H2O

mols KHP = grams/molar mass
mols NaOH = mols KHP (look at the coefficients in the balanced equation.)
M NaOH = mols NaOH/L NaOH

To find the molarity of NaOH (sodium hydroxide) solution, we need to use the given information about the volume of NaOH solution and the mass of the substance it reacted with. Here's how you can calculate it:

Step 1: Convert the mass of KHP to moles.
- Given: mass of KHP = 0.300 g
- Molar mass of KHP = 204.2 g/mol
- Moles of KHP = mass of KHP / molar mass of KHP

Step 2: Determine the moles of NaOH that reacted.
- Since the balanced chemical equation is not provided, I will assume that the reaction between NaOH and KHP is a 1:1 ratio of moles.
- Therefore, the moles of NaOH = moles of KHP

Step 3: Calculate the molarity of NaOH.
- Molarity (M) is defined as moles of solute divided by the volume of the solution in liters.
- Given: volume of NaOH solution = 12.5 mL = 0.0125 L
- Molarity of NaOH (M) = moles of NaOH / volume of NaOH solution

By following these steps, you can find the molarity of NaOH.