Posted by Savannah on Tuesday, December 11, 2012 at 12:33pm.
Vb = 4m/s @ 180o + 3m/s @ 90o.
X = 4*cos180 + 3*cos90 = -4 m/s.
Y = 4*sin180 + 3*sin90 = 3 m/2.
tanAr = Y/X = 3/-4 = -0.7500
Ar = 36.87o = Reference angle.
A = 180 - 36.87 = 143o.
Vb = X/cosA = -4/cos143 = 5 m/s.
Related Questions
Physics - A current of a river flows steadily from west to east at 1.00 m/s. A ...
Physics - A motorboat heads due east at 8.5 m/s across a river that flows to the...
physics - A 200-m-wide river flows due east at a uniform speed of 4.9 m/s. A ...
physics - A 200-m-wide river flows due east at a uniform speed of 2.0 m/s. A ...
Physics - A boater wants to head straight across a river that has a current of ...
Physics - A boat is traveling with a speed 7.2 mph over the water and at a ...
physics - A motor boat heads east across a river at 5.1 m/s. The river flows ...
Physics - A boat travels at 3.8 m/s and heads straight across a river 240m wide ...
Physics - A boat travels at 3.8 m/s and heads straight across a river 240m wide ...
Physics - A boat travels at 3.8 m/s and heads straight across a river 240m wide ...
For Further Reading