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March 25, 2017

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A skydiver deploys his parachute when he is 950m directly above his desired landing spot. He then falls through the air at a steady 5.0 m/s . There is a breeze blowing to the west at 1.1 m/s.

At what angle with respect to vertical does he fall?

By what distance will he miss his desired landing spot?

  • Physics - ,

    a. Vo = 5m/s @ 270o + 1.1m/s @ 180o.

    X = 5*cos270 + 1.1*cos180 = -1.1 m/s.
    Y = 5*sin270 + 1.1*sin180 = -5 m/s.

    tanAr = Y/X = -5/-1.1 = 4.54545
    Ar = 77.6o = Reference angle.
    A=180 + Ar = 180 + 77.6 = 257.6o, CCW.
    A = 270 - 257.6 = 12.4o West of South.

    b. Vo = -1.1/cos257.6=5.12 m/s @ 257.6o
    Xo = 5.12*cos257.6 = -1.1 m/s.
    Yo = 5.12*sin257.6 = -5.0 m/s.

    h = Vo*t + 0.5g*t^2 = 950 m.
    -5t + 4.9t^2 = 950
    4.9t^2 - 5t -950 = 0
    Use Quadratic formula:
    Tf = 14.4 s. = Fall time.

    Dx = Xo * Tf = -1.1m/s * 14.4=1.1 m.=
    1.1m West of desired landing spot.

  • Physics - ,

    Yoe = 364(66)

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