Posted by Aaron on Tuesday, December 11, 2012 at 12:29pm.
A skydiver deploys his parachute when he is 950m directly above his desired landing spot. He then falls through the air at a steady 5.0 m/s . There is a breeze blowing to the west at 1.1 m/s.
At what angle with respect to vertical does he fall?
By what distance will he miss his desired landing spot?

Physics  Henry, Thursday, December 13, 2012 at 9:22pm
a. Vo = 5m/s @ 270o + 1.1m/s @ 180o.
X = 5*cos270 + 1.1*cos180 = 1.1 m/s.
Y = 5*sin270 + 1.1*sin180 = 5 m/s.
tanAr = Y/X = 5/1.1 = 4.54545
Ar = 77.6o = Reference angle.
A=180 + Ar = 180 + 77.6 = 257.6o, CCW.
A = 270  257.6 = 12.4o West of South.
b. Vo = 1.1/cos257.6=5.12 m/s @ 257.6o
Xo = 5.12*cos257.6 = 1.1 m/s.
Yo = 5.12*sin257.6 = 5.0 m/s.
h = Vo*t + 0.5g*t^2 = 950 m.
5t + 4.9t^2 = 950
4.9t^2  5t 950 = 0
Use Quadratic formula:
Tf = 14.4 s. = Fall time.
Dx = Xo * Tf = 1.1m/s * 14.4=1.1 m.=
1.1m West of desired landing spot.

Physics  Hr, Wednesday, April 30, 2014 at 11:34am
Yoe = 364(66)
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