Posted by **Knights** on Tuesday, December 11, 2012 at 11:17am.

In a chess variant, a "lord" can move one space at a time, either upward, or to the right, or diagonally upward and to the right. How many ways are there for a lord to move from the bottom left to top right corner of the 8 by 8 chessboard?

Thanks in advance for helping me!

- A probability question i think -
**Steve**, Tuesday, December 11, 2012 at 11:27am
Each move advances either upward or rightward or both. If there are n diagonal moves, then there are 14-n up or right moves. So, there may be 0 to 7 diagonal moves, and the rest can be chosen in two ways.

so, there are

(0+2^14) + (1+2^12) + (2+2^10) + ... + (7+0) = 21872

- A probability question i think -
**Knights**, Tuesday, December 11, 2012 at 11:29am
ok thanks alot steve you really help alot

- A probability question i think -
**Someone in the world**, Tuesday, December 18, 2012 at 8:34pm
steve is wrong...

- A probability question i think -
**Steve is wrong**, Saturday, August 17, 2013 at 10:51am
You are wrong

- A probability question i think -
**S_Dog**, Wednesday, August 21, 2013 at 7:12pm
You guys....actually try to help out please.

Here, make a chart that cascades to the upper-right-most square. Kinda like Pascal's Triangle.

1............. 48639

1...................

1...................

1...................

1 7 25..............

1 5 13 .............

1 3 5 7 9...........

1 1 1 1 1 1 1 1 1 1 1

So the answer is 48639.

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