On the moon the surface temperature ranges from 395 K during the day to 1.02 x 102 K at night. Convert these temperatures to the Celsius and Fahrenheit scales. (a) 395 K in degrees Celsius; (b) 395 K in degrees Fahrenheit; (c) 1.02 x 102 K in degrees Celsius; (d) 1.02 x 102 K in degrees Fahrenheit.

C = K + 273.15

F = 9/5 C + 32 = 9/5 K + 491.67

so, what do you get?

To convert temperatures from Kelvin (K) to Celsius (°C), you simply need to subtract 273.15 from the temperature in Kelvin. To convert temperatures from Celsius to Fahrenheit (°F), you can use the formula:

°F = (°C * 9/5) + 32.

Now, let's solve each part of the question:

(a) To convert 395 K to degrees Celsius:
°C = 395 - 273.15 = 121.85°C

(b) To convert 395 K to degrees Fahrenheit:
°F = (121.85 * 9/5) + 32 ≈ 251.33°F

(c) To convert 1.02 x 10^2 K to degrees Celsius:
°C = (1.02 x 10^2) - 273.15 = -171.15°C

(d) To convert 1.02 x 10^2 K to degrees Fahrenheit:
°F = (-171.15 * 9/5) + 32 ≈ -276.07°F

Please note that temperatures on the moon do not actually reach these extreme values, and this is just an example for the purpose of answering the question.