Tuesday

March 3, 2015

March 3, 2015

Posted by **Anamika** on Tuesday, December 11, 2012 at 6:59am.

- differentiation -
**Reiny**, Tuesday, December 11, 2012 at 7:52amlooks like triple product rule

recall

d(uvw) = uvw' + uwv' + vwu'

I will also assume that you meant ln(x+y)

xy ln(x+y) = 1

xy(1/(x+y)) * (1 + dy/dx) + x ln(x+y) dy/dx + y ln(x+y) = 0

expand the first part to get at the dy/dx

xy(1/(x+y)) + dy/dx xy(1/(x+y)) + dy/dx (x ln(x+y)) = -y ln(x+y) - xy(1/(x+y))

dy/dx [xy(1/(x+y)) + (x ln(x+y)) ] = -y ln(x+y) - xy(1/(x+y))

dy/dx = (-y ln(x+y) - xy(1/(x+y))) / [xy(1/(x+y)) + (x ln(x+y)) ]

leave it like that or simplify as needed.

**Answer this Question**

**Related Questions**

math - Logarithm!!! Select all of the following that are true statements: (a) ...

Math Help Please - Which of the following expressions is equal to log (x sqrt-y...

math - Q1:solve log(5)x-log(25)(x+10) = 0.5 Q2:If 2log(a)x=1+log(a) (7x-10a) ,...

Mathematics - Prove that log a, log ar, log ar^2 is an a.p. Is the following ...

calculus - use implicit differentiation to find dy/dx . Then evaluate the ...

Algebra 2 - how do not understand how to do this Log X + Lob (X-3) = 1 I know I ...

math(Please help) - 1) use the properties of logarithms to simplify the ...

math - write as a single logarithm: -2logbase3(1/x)+(1/3)logbase3(square root of...

Calculus 1 - implicit differentiation - I do not understand implicit ...

Calculus 1 - implicit differentiation - I do not understand implicit ...