posted by Odesa on .
The fictitious compound, pandemonium fluoride ( PnF2 ) has a Ksp value in water of 3.091x10^-9 M^3 at room temperature. Calculate the solubility of PnF2 in water. Express your answer in units of molarity.
How would you expect the solubility of pandemonium fluoride to vary in water that is warmer than room temperature?
i)The solubility should not change, as the solubility is solely a property of the solute and solvent. It would be invariant with temperature.
ii)The solubility would likely decrease.
iii)The solubility would likely increase.