Posted by **Eric** on Tuesday, December 11, 2012 at 1:02am.

Write five 7-digit numbers that are even. The sum of the digits in each number is 29.

- Math -
**Steve**, Tuesday, December 11, 2012 at 5:03am
all you have to do is come up with 1 such number, then shuffle the digits around, leaving the last (even) digit alone.

6152438

now shuffle the digits, leaving 8 where it is. There are 6! = 720 ways to do it.

It was easy to come up with, since 29-8=21, so I just picked 3 pairs of digits that add up to 7, and stuck 'em in front of the 8.

- Math -
**Eric**, Tuesday, December 11, 2012 at 9:48am
Thank you for your response. But, I just don't understand what you wrote. It seems completely different than what the question is asking. Because the statement says all 7 numbers are even?

- Math -
**Eric**, Tuesday, December 11, 2012 at 10:16am
Thank you Eric!! I understand after thinking about your solution. You are 100% correct!!! :=)

- Math -
**Steve**, Tuesday, December 11, 2012 at 10:44am
good job. Thanks for puzzling it out on your own.

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