posted by Eric on .
Write five 7-digit numbers that are even. The sum of the digits in each number is 29.
all you have to do is come up with 1 such number, then shuffle the digits around, leaving the last (even) digit alone.
now shuffle the digits, leaving 8 where it is. There are 6! = 720 ways to do it.
It was easy to come up with, since 29-8=21, so I just picked 3 pairs of digits that add up to 7, and stuck 'em in front of the 8.
Thank you for your response. But, I just don't understand what you wrote. It seems completely different than what the question is asking. Because the statement says all 7 numbers are even?
Thank you Eric!! I understand after thinking about your solution. You are 100% correct!!! :=)
good job. Thanks for puzzling it out on your own.