posted by Gurjot on .
calculate the mass of solid NaCl that must be added to 1.50L of a 0.100M AgNO3 solution to precipitate all the Ag+ ions in the form of AgCl. calculate the mass of AgCl formed.
AgNO3 + NaCl ==> NaNO3 + AgCl
mols AgNO3 = M x L = ?
Using the coefficients in the balanced equation, convert mols AgNO3 to mols NaCl. Then grams NaCl needed = mols NaCl x molar mass NaCl.
Use the same process for grams AgCl formed.