Sunday

December 21, 2014

December 21, 2014

Posted by **Christina** on Monday, December 10, 2012 at 9:12pm.

- ALGEBRA 2 urgent!! -
**Mac**, Monday, December 10, 2012 at 10:20pm8x+5y=200

X=length of one rectangle

Y=width of one rectangle

Area = xy

Y= (200-8x)/5

Area=x (200-8x)/5

Hope this gets you going

**Answer this Question**

**Related Questions**

Math - if you have 200 feet of fencing to enclose four adjacent rectangular ...

Pre Calculus - He needs two adjacent rectangular enclosures - he has 300 feet of...

MATH ANALYSIS - How should this be done? Suppose you have 132 m of fencing with ...

MATH ANALYSIS - How should this be done? Suppose you have 132 m of fencing with ...

Algebra 2 - A farmer wants to enclose 2 adjacent rectangular regions next to a ...

advanced math - Suppose you have 168 meters of fencing with which to make two ...

optimization - A farmer wants to make 9 identical rectangular enclosures as ...

College Algebra and Trig - a rancher has 12,000 feet of fence to enclose 5 ...

Algebra - Algebra Word Problems: 1. The length of the floor of a one-storey ...

Precalculus - A builder has 600 feet of fencing to enclose three adjacent ...