Before the force is applied (t < 0 on the graph), the particle moves along the X axis with velocity V1 = -6.6 m/s. Find the velocity V2 of the particle after force stops acting on it. (t > 9s)
To find the velocity V2 of the particle after the force stops acting on it (t > 9s), we need to use kinematic equations.
Given:
Initial velocity V1 = -6.6 m/s
We know that the force causes a change in velocity, and when the force stops acting, the particle will continue to move at a constant velocity. Therefore, V2 will be equal to V1.
So, the velocity V2 of the particle after the force stops acting on it is -6.6 m/s.
To find the velocity (V2) of the particle after the force stops acting on it (t > 9s), we need to analyze the given information and use the equations of motion.
First, let's break down the information given in the problem:
V1 = -6.6 m/s: This is the initial velocity of the particle before the force is applied. The negative sign indicates that the particle is moving in the negative direction along the X-axis.
t > 9s: This tells us that we need to find the velocity of the particle after 9 seconds.
To find the velocity after the force stops acting, we can use the equation of motion:
V2 = V1 + a * t
Where:
V2 is the final velocity of the particle.
V1 is the initial velocity of the particle.
a is the acceleration experienced by the particle.
t is the time period.
In this case, since the force stops acting on the particle, the acceleration is zero (a = 0).
Therefore, the equation simplifies to:
V2 = V1 + 0 * t
V2 = V1
So, the velocity (V2) of the particle after the force stops acting on it (t > 9s) is the same as the initial velocity (V1) before the force was applied. In this case, V2 = -6.6 m/s.