Posted by Amy on Monday, December 10, 2012 at 3:57pm.
Use a) for your hypotheses.
You can try a proportional one-sample z-test since this problem is using proportions.
Using a formula for a proportional one-sample z-test with your data included, we have:
z = .16 - .15 -->test value (150/940) is .16) minus population value (.15) divided by
√[(.15)(.85)/940] --> .85 represents 1-.15 and 940 is sample size.
Finish the calculation.
Use a z-table to find the p-value. The p-value is the actual level of the test statistic.
Check a z-table for the critical value at .05 level of significance for a one-tailed test. Compare the test statistic you calculated to the critical value from the table. If the test statistic exceeds the critical value, reject the null and conclude p>0.15 (there is sufficient evidence to support the claim); if the test statistic does not exceed the critical value from the table, do not reject the null (there is not sufficient evidence to support the claim).
I'll let you take it from here.
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