posted by cris on .
How much would the rope stretch to break the climber's fall if he free falls 2m before the rope runs out of slack? k=1.40x10^4N//m
mass of man= 90 kg
I forgot how to use conservation of energy for this. I tried it, but I did it wrong.
x = 1/2*g*t^2 = 2 = 4.9*t^2
Solve for t, the time then solve for the climber's speed v using
v = 9.8*t
1/2*m*v^2 = 1/2*k*xstretch^2; where xstretch is the amount that the rope will stretch