Posted by huda on .
f(x)=x^610*x^57*x^4+80*x^3+12*x^2192*x
how to find the answer an its graph???

calculus 
Steve,
y = x^610x^57x^4+80x^3+12x^2192x
= x(x^510x^47x^3+80x^2+12x192)
you know any rational roots will be factors of 192. There appear to be none except x=0.
If you visit wolframalpha.com and enter the formula, you will find one root near x=10, but that is the only real nonzero root.
To see what happens near x=0, try visiting
http://rechneronline.de/functiongraphs/
set the x range 10 to 10
y 1000 to 1000