Posted by **Elizabeth** on Monday, December 10, 2012 at 10:16am.

A motorist makes a journey of 240 km from Singapore to Malacca to visit his inlaws at an average speed of x kilometers.

On his return journey, his average speed is reduced by 6km/hour due to traffic.

If the return journey takes 20 minutes longer, form an equation with x and solve it to find the average speed of each journey, giving your answer correct to two decimal places.

So: 240/x is the number of hours taken for the first journey.

240/x-6 is the time it takes for the return journey.

What do I do next? Please help!

- Math -
**Steve**, Monday, December 10, 2012 at 10:31am
and you know that the return journey takes 1/3 hour longer than the one going.

240/x + 1/3 = 240/(x-6)

x = 3(1+±481) = 68.80

check:

240/62.80 = 3.82

240/68.80 = 3.49 = 3.82

difference: .33 hr = 20 min

you got the setup right, but didn't take that final step. Be sure to analyze **everything** they tell you, and the solution will emerge.

- Math -
**Steve**, Monday, December 10, 2012 at 10:32am
oops. typo that's

3(1±√481)

- Math -
**Elizabeth**, Monday, December 10, 2012 at 10:48am
thanks!

- Math -
**ammar**, Sunday, December 7, 2014 at 3:37am
dhek bhai phely minutes ko convert kro phir jo answer aye us ko 240se add kr k equation se agey solve krlo

- Math -
**titu mir**, Sunday, December 7, 2014 at 3:39am
galat galat ammar galat

- Math -
**Anonymous**, Monday, May 2, 2016 at 6:11am
kk thanks

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